Suppose the position of an object moving in a straight line is given by s left parenthesis t right parenthesis equals 5 t squared plus 2 t plus 2. Find the instantaneous velocity when t equals 6. What expression can be used to find the instantaneous velocity at the given time?

v(6) = 62

At any given time: v(t) = 10t + 2

Step-by-step explanation:

The equation that describes the position of the object is:

The instantaneous velocity at any given time, v(t), is the derivate of the position expression:

For t = 6, the instantaneous velocity is:

The instantaneous velocity when t=6 is v(6) = 62 units of distance/units of time.

lol we need to see what the question is asking about

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15