Suppose that the probability of getting a job offer (from a specific company) is 0.16. Suppose that we observe empirically that given that an applicant for the job was in fact offered a job, the probability of an on campus interview was 0.93. Also, we observe empirically that given the group that were not offered a job the probability of an on campus interview was of 0.08. Given that a person got a campus interview, what is the probability that they get a job offer? (Answer to five decimal places).

0.68889

Step-by-step explanation:

This can be formulated as the following question:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

So

Given that a person got a campus interview, what is the probability that they get a job offer?

P(B) is the probability of getting a job offer. So

P(A/B) is the probability of getting a campus interview, given that they get a job offer. So P(A/B) = 0.93.

P(A) is the probability ofgetting a campus interview. Of those 16% who got a job, 93% had a campus interview. Of those 84% who did not get a job, 8% had a campus interview. So

Finally

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.