Arielle is building the wooden framework for the roof of a house. she needs the angle created by the vertical and horizontal boards of the frame to be a right angle. the height of the vertical board is 12 feet. the length of the horizontal board is 15 feet. the support beam that will connect the ends of the two boards measures 20 feet. which is true regarding the triangular frame? it is an acute triangle. about 0.8 foot needs to be removed from the 20-foot board to create a right triangle. it is an obtuse triangle. about 0.8 foot needs to be removed from the 20-foot board to create a right triangle. it is an acute triangle. about 7 feet need to be removed from the 20-foot board to create a right triangle. it is an obtuse triangle. about 7 feet need to be removed from the 20-foot board to create a right triangle.

It is an acute triangle. about 0.8 foot needs to be removed from the 20-foot board to create a right triangle.

Step-by-step explanation:

Since, if she want a right angle created by the vertical and horizontal boards of the frame to be a right angle.

Then, By the Pythagoras theorem,

The vertical board, horizontal board and the support beam must has the below relation,

Here the length of vertical board = 12 feet, the length of horizontal board = 15 feet and the length of support team = 20 feet

But,

Hence, the angle between vertical and horizontal board is acute.

Since, 20 - 19.2093727123 = 0.790627288≈ 0.8

Hence, we need to cut the support beam by approx 0.8 feet to make right angle between vertical board and horizontal board.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

constants mean the stopped points or the points on a graph that nothing is changing, hope this

step-by-step explanation: