Prove that:
b
5^31–5^29 is divisible by 100.

5^31 5^29 = 5^29*(25 - 1) = 24*25*5^27 = 600*5^27 = 6*5^27*100

Step-by-step explanation:

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.

hi there!

the answer to this question is d: 35

step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35