Formulate but do not solve the following exercise as a linear programming problem. Ace Novelty manufactures Giant Pandas and Saint Bernards. Each Panda requires 1.5 yd2 of plush, 30 ft3 of stuffing, and 5 pieces of trim; each Saint Bernard requires 2 yd2 of plush, 35 ft3 of stuffing, and 8 pieces of trim. The profit for each Panda is $20 and the profit for each Saint Bernard is $30. If 3600 yd2 of plush, 66,000 ft3 of stuffing and 13,600 pieces of trim are available, how many of each of the stuffed animals should the company manufacture to maximize profit P in dollars? (Let x represent the number of Giant Pandas to be manufactured and y represent the number of Saint Bernards to be manufactured.) Maximize P = 20x+30y subject to the constraints plush stuffing trim x ≥ 0 y ≥ 0

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8

answer:

total cost for tiles and paints is $924.  

step-by-step explanation:

we have been given that a community hall is in the shape of a cuboid. the hall is 40m long 15m high and 3m wide.

the paint will be required for 4 walls and ceiling.

let us find area of walls and ceiling.

therefore, the area of walls and ceiling is 1410 square meters.

given: cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. therefore,

therefore, the total painting cost is $564.

tiles will be required for floor. let us find the area of floor.

given: 1m squared floor tiles costs $3. so,

therefore, the total tiles cost is $360.

now let us find combined total cost of tiles and paint.

therefore, the combined total cost of tiles and paint is $924.

do it yourself this is easy

step-by-step explanation: