What are the exact solutions of x2 − 5x − 1 = 0 using x equals negative b plus or minus the square root of the quantity b squared minus 4 times a times c all over 2 times a? x = the quantity of 5 plus or minus the square root of 29 all over 2 x = the quantity of negative 5 plus or minus the square root of 29 all over 2 x = the quantity of 5 plus or minus the square root of 21 all over 2 x = the quantity of negative 5 plus or minus the square root of 21 all over 2

x = the quantity of 5 plus or minus the square root of 29 all over 2

Step-by-step explanation:

The given quadratic equation is expressed as

x² - 5x - 1 = 0

The equation is already in the standard form of ax² + bx + c

The general formula for solving quadratic equations is expressed as

x = [- b ± √(b² - 4ac)]/2a

From the given quadratic equation,

a = 1

b = - 5

c = - 1

Therefore,

x = [- - 5 ± √(- 5² - 4 × 1 × - 1)]/2 × 1

x = [5 ± √(25- - 4)]/2

x = [5 ± √29]/ 2

x = ( 5 + √29)/- 2 or x = (5 - √29)/2

answer: a clock

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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