The uncertainty principle is LaTeX: \Delta x\Delta p\ge\frac{h}{4\pi}Δ x Δ p ≥ h 4 π. Based on this relationship, if a measurement of the momentum (p) is more precise (i. e., LaTeX: \Delta pΔ p is smaller), then what will be observed about the measurement of the position (x)?

The measurement of the position will be less precise, that is to say, Δx will be bigger.      

Step-by-step explanation:

The uncertainty principle:

        (1)

This uncertainty principle means that it is not possible to measure or predict the position (x) and momentum (p) simultaneously with arbitrary certainty, that is to say, the product of the uncertainties Δx and Δp must be greater than or equal to h/4π.        

From equation (1) we have that these uncertainties can not be equal to zero and if one of them becomes small, the other will become large, so that its product will be greater than or equal to h/4π.                  

Therefore, of the above if a measurement of the momentum is more precise, that is to say, Δp is smaller, the measurement of the position will be less precise, that is to say, Δx will be bigger.                        

I hope it helps you!              

1.true 2.false? ? i think. .

step-by-step explanation: