When parking a car in a downtown parking lot, drivers pay according to the number of hours or fraction thereof. The probability distribution of the number of hours cars are parked has been estimated as follows:

A. Mean=

B. Standard Deviation=

The cost of parking is 5 dollars per hour. Calculate the mean and standard deviation of the amount of revenue each car generates.

A. Mean=

B. Standard Deviation

col1 X 1 2 3 4 5 6 7 8
col2 P(X) 0.229 0.113 0.114 0.076 0.052 0.027 0.031
0.358

a) Mean number of hours = 4.604 hours, Standard deviation = 2.9033 hours

b) Mean value of revenue = $23.02, Standard deviation = $14.5165

Step-by-step explanation:

We are given the following in the question:

X:            1         2          3         4            5           6          7          8

P(X):   0.229   0.113   0.114   0.076   0.052   0.027   0.031     0.358

a) Mean =

Variance =

b) The cost of parking is 5 dollars per hour.

Mean of revenue each car generates =

Standard deviation of revenue each car generates =

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

answer:

125 yards

explanation:

75+50=125. that is my answer