Erin, Elizabeth, and Anna are playing a game. Their probabilities of winning the game are as follows:
\text{P(Erin wins}) = 0.3P(Erin wins)=0.3start text, P, left parenthesis, E, r, i, n, space, w, i, n, s, end text, right parenthesis, equals, 0, point, 3
\text{P(Anna wins}) = \dfrac12P(Anna wins)=
2
1

start text, P, left parenthesis, A, n, n, a, space, w, i, n, s, end text, right parenthesis, equals, start fraction, 1, divided by, 2, end fraction
\text{P(Elizabeth wins}) = 20\%P(Elizabeth wins)=20%

The answer to this question is Elizabeth last , Erin second and Anna First

Elizabeth 20%

Erin 0.3= 30%

Anna 1/2= 50%

Khan Academy Struggles

Step-by-step explanation:

Question is incomplete and not well presented.

Erin, Elizabeth, and Anna are playing a game. Their probabilities of winning the game are as follows:

P(Erin wins)=0.3

P(Anna wins)= 1/2

P(Elizabeth wins)=20%

Which of these events is the least likely possible?

Step-by-step explanation:

Given that

P(Erin wins)=0.3

P(Anna wins)= 1/2

P(Elizabeth wins)=20%

First, we convert all probabilities to decimal

P(Erin wins) = 0.3

P(Anna wins) = 0.5

P(Elizabeth wins) = 0.2

The event with the least likelihood is the event whose probability is smallest.

If we observe and compare the values of the three probabilities, it'll be noticed that the probability of Elizabeth winning is the least.

Hence, P(Elizabeth) = 20% is the least likely possible

muyb ajo

step-by-step explanation:

jegosu

positive

step-by-step explanation:

the quadrant is facing upwards