From a bag containing 5 nickels, 8 dimes, and 7 quarters, 5 coins are drawn at random and all at once. What is the probability of getting 2 nickels, 2 dimes, and 1 quarter?

0.13

Step-by-step explanation:

From a bag containing 5 nickels, 8 dimes, and 7 quarters, 5 coins are drawn at random and all at once

we need to select 2 nickels from 5 nickels and select 2 dimes from 8 dimes and 1 quarter from 7 quarters

There are total of 5+8+7=20 coins

select 5 coins from total of 20 coins

2 nickels can be selected from 5 nickels in 5C2 ways

2 dimes selected from 8 dimes

1 quarter selected from 7 quarter

5 coins selected from 20 coins

probability of getting 2 nickels, 2 dimes, and 1 quarter

y/x of point b= y/x of point a

step-by-step explanation:

(i got the same question, this was the correct answer.)

it would be 3 ÷by 6 because the number on each side