What is the average rate of change of the function f(x)=x^(2)-12x+16 between x=7 and x=11?

The mean value of this function on the interval [7, 11] is 6.

Step-by-step explanation:

The given function f(x)= x^2 - 12x + 16 has the value

f(7)= 7^2 - 12(7) + 16, or -19, at x = 7.  Thus, one point on the curve is (7, -19).

The given function f(x) = x^2 - 12x + 16 has the value

f(11)= 11^2 - 12(11) + 16, or 5, at x = 11.  The second point on the curve is (11, 5).

Using the mean value formula, we get:

f(11) - f(7)       5 - (-19)

= = 24/4 = 6

    11 - 7              4

The mean value of this function on the interval [7, 11] is 6.

one that is bigger than 3 1/2