Y = C1 cos 2x + c2 sin 2x is a two-parameter family of solutions of the second-order DE y'" + 4y = 0. If possible, find a solution of the differential equation that satisfies the given side conditions. The conditions specified at two different points are called boundary conditions. 0, y(T) 0 40. y(0) 39. y(0) 0, y(T/4) 3 42. y(0) = 1, y'(m) - 41. y'(0) 0, y'(7/6) 0 44. y'(T/2) 1, y'(m) = 0 43. y(0) 0, y(T) = 2

idk

step-by-step explanation:

do it yourself, cause that made me do it myself today, in english!

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

step-by-step explanation:

i have no idea just need points sorry

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