Find three consecutive odd intergers such that the sum of the largest and twice the smallest is 25

Let the consecutive odd integers be:

x ,  x + 2,  x + 4.            Each integer increases by 2

Sum of largest and twice the smallest = 25

(x + 4) + 2*(x) = 25

x + 4 + 2x = 25

x + 2x = 25 - 4

3x = 21

x = 21/3

x = 7

Recall the consecutive odd integers are   x,  x + 2,  x +4

7,  7 + 2 = 9,  9 + 2= 11

7, 9, 11.