Four students attempt to register online at the same time for an Introductory Statistics class that is full. Two are freshmen and two are sophomores. They are put on a wait list. Prior to the start of the semester, two enrolled students drop the course, so the professor decides to randomly select two of the four wait list students and gives them a seat in the class. What is the probability that both students selected are freshmen?
a.
b.
c.
d.

a.

Step-by-step explanation:

To know the combined probability we myltiply the chances of the first positive outcome and multiply it by the chance of the second positive outcome:

the probability in the first case will be of 2 positive outcome (there are two freshmen) over 4 possible outcome:  2/4 = 1/2

for the secodn case, there will be a single positive outcome (one of the freshmen was picked already) over 3 possible outcome (the freshmen and the two sophomores = 1/3

We now calculate:

2/4 x 1/3 = 2/12 = 1/6

898.1666667

step-by-step explanation:

5389/6 = 898.1666667

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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