The equation d = 3t gives the distance, d, in meters that Liam swims with respect to time, t, in seconds.

The table gives the different distances in meters that Edgar swam with respect to time in seconds.
Time (seconds) Distance (meters)
20 64
40 128
60 192

Assume that Liam and Edgar both swim at a constant rate.

What is the rate of change for each swimmer in terms of meters per second? Who swims faster?

Be sure to label your answers with the name of the swimmer.

Liam's rate = 3 meters per second

Edgar's rate = 3.2 meters per second

Edgar swims faster

Step-by-step explanation:

Liam:

The equation gives the distance, d, in meters that Liam swims with respect to time, t, in seconds.

When

When

Rate of change:

Liam's rate is 3 metres per second.

Edgar:

When

When

Rate of change:

Edgar's rate is 3.2 metres per second.

Edgar swims faster.

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.

idk

step-by-step explanation: