Please help as soon as possible with these 5 questions about Pythagorean Theorem. Thank you so much! Brainliest guaranteed! :)

1: 12.96

2: 32.25

3: 169

4: 77mi

5: 65

Step-by-step explanation:

1:a^2+b^2=c^2 -> 17^2-11^2=a^2 ->sqrt of 168=a=12.96

2: 16^2+28^2=c^2 -> \sqrt{1040} =c=32.25

3:5^2+12^2=13^2 -> 169=169

4: you can form a triangle with this problem: 44mi=b and 63mi=a so you need to find c

black lol

step-by-step explanation:

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(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240