60 randomly selected students were asked how many siblings were in their family. Let X = the number of pairs of siblings in the student's family. The results are as follows: Siblings1 2 3 4 5 6 7 Frequency 13 22 15 6 3 0 1 Round your answers to two decimal places. The mean is: The median is: The sample standard deviation is: The first quartile is: The third quartile is: What percent of the respondents have had less than 3 siblings? % 20% of all respondents have had at most how many siblings?

Step-by-step explanation:

From the information on 60 students we write frequency distribution as

x       1        2        3        4          5             6     7    total

f        13      22      15        6          3             0     1      60

C      13       35      50     56       59           59    60

xf      13      44     45      24        15             0     7      148

x^2f  13      88    135     96       75             0   49       456

Mean = 2.67

Var = 445.92

Std dev = 21.21

I quartile = 2

III quartile = 3

20% have atmost 1

a_n = a_1 + (n - 1)d

the first term is 6.

the common difference d = ?

when you find d, replace n with 7 and d with the common difference to find your answer.