If some function f has the tangent line y − 2 = 4(t − 16) at the point implied by the equation, what are f (16) and f ′(16)?

f(16) = 2

f'(16) = 4

Step-by-step explanation:

Given:

- The function f(x) is given as:

                                   f(x) = y = 4t - 62

Find:

- what are f (16) and f ′(16)?

Solution:

- The value f(16) is given by plugging in x = 16 into the expression given as follows:

                                  f(16) = 4*16 - 62

                                  f(16) = 2

- The value of f'(16) is the gradient of the function @ x = 16.

The gradient is given by the derivative of the function:

                                  df(x) / dx = 4

Hence, f'(x) is in-dependent of the value of x and gradient is 4 for all values of x.

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743

answer: a. 13/44

step-by-step explanation: judging by the information given to us, we are looking for experimental probability. we can see that 13 males have chosen chocolate ice cream. there are 44 ice creams in total (remember that the total is always the denominator). so our answer is 13/44.