The perimeter of a rectangle sandpit is 40 meters. The length of the sandpit is 1 meter less than twice it's width. What are the dimensions of this sandpit

L = 15, W = 8

Step-by-step explanation:

Perimeter = 2(L + W)

P = 40

L = 2W - 1

40 = 2((2W-1) + W)

40 = 4W - 2 + 2W

40 = 6W - 2

42 = 6W

W = 8

Since L = 2W - 1

L = 2(8) - 1

L = 15

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x