A square has a perimeter of 28 units, an area of 49 units(2), and sides that are either horizontal or vertical. The vertices are all located in the same quadrant where the X value is negative. What are the possible coordinates of the square?

a. ∀ x≤0 ∧ ∀ y ∈ IR + ∪ 0

b. ∀ x≤0 ∧ ∀ y ∈ IR -

c. ∀ x≤0 ∧ ∀ y -∞ → +∞

Step-by-step explanation:

P=4l ⇒ 28=4l ⇔ l=28/4 =7

A=l.l=7*7=49

As can be seen in the graph so that x is negative, it must be fulfilled that its values are located in the second and third quadrants and their values must be less than zero and also the values of y can be all positive and negative real numbers

Possible coordinates:

a. ∀ x≤0 ∧ ∀ y ∈ IR + ∪ 0

for all x less iqual than zero and all positive real y including zero

b. ∀ x≤0 ∧ ∀ y ∈ IR -

for all x less iqual than zero and all y negative reals

c. ∀ x≤0 ∧ ∀ y -∞ → +∞

for all x less equal than zero and all y from minus infinite to plus infinite