A system has a continuous load requirement of 80 MW. Find the expected load loss and the probability of load loss (loss of load probability) if the generation system is composed of nine 10 MW units each with an unavailability (probability of failure) of 1.5%.

Expected load loss = 1.35

P (Load Loss) = 0.127

Step-by-step explanation:

The probability of failure is: q = 0.015

The probability of success is: p = 1 - q = 1 - 0.015 = 0.985

The number of units the generation system is composed of is, n = 9.

The capacity of each unit is 10 MW.

Let X = number of units that failed or are unavailable.

The random variable X follows a Binomial distribution with parameters n and q.

The probability function is:

; x =0, 1, 2, 3...

Then the expected load loss is:

Thus, the expected load loss is 1.35.

The probability that at least one unit fails is:

P (X ≥ 1) = 1 - P (X < 1) = 1 - P (X = 0)

Thus, the probability of load loss is 0.127.

i think asking google will you get the answer to that question

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.