A collection of jewelry includes two rings, one 18 years old and the other 46 years old. In how many years will the older ring be twice as old as the newer ring?

In 10 years.

Step-by-step explanation:

1. 46-18=28

2. 28 (2)= 56

3. 56-46=10

(4. 18+10=28)

5. So, after 10 years, the older ring will be 56 years old and the younger ring will be 28 years old. 56 is twice as much as 28. (28+28=56, 28(2)=56 or 56/2=28)

answer:   rotate 270° clockwise about (7, 1) and reflect across the line x = 7

step-by-step explanation:

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