There is a 0.23 probability that a typical convenience store customer buys gasoline. The probability that a customer buys groceries is 0.76 and the conditional probability of buying groceries given that the customer buys gasoline is 0.85.

a) Find the probability that a typical customer buys both gasoline and groceries.

The probability that a typical customer buys both gasoline and groceries, P(Ga n Gr) = 0.1955

Step-by-step explanation:

Let the probability that a customer guys groceries be represented by P(Gr) and that of buying gasoline be P(Ga)

Given

P(Gr) = 0.76

P(Ga) = 0.23

P(Gr|Ga) = 0.85

For mutually exclusive events,

P(B|A) = (P(B n A))/P(A)

P(Gr|Ga) = (P(Gr n Ga))/P(Ga)

P(Gr n Ga) = P(Gr|Ga) × P(Ga)

P(Gr n Ga) = 0.85 × 0.23 = 0.1955

Hope this Helps

answer: 94

step-by-step explanation: 79+91+92+94+94 = 450 divided by 5 (since there are 5 number that are being added) = 90

my dear correct answer is option number 3