A movie with an aspect ratio of 1.15:1 is shown as a pillarboxed image on a 49-inch 4:3 television. Calculate
the height of the image, the area of the image, the width of each black bar at the sides of the screen,
area of each black bar on the screen, and area of the TV
Height of the image.

_Area of the image.

_Width of each black bar.

_Area of each black bar.

_Area of the television.

_% of the screens area occupied by the image

he sells x mount because thats eqivilqant to the maz and then divided into quarters

step-by-step explanation:

1; 35 is the ratio

step-by-step explanation:

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west

i’ll just s take the points thxs