A person who is 6 feet tall walks away from a flagpole toward the tip of the shadow of the flagpole. When the person is 12 feet from the flagpole, the tips of the person's shadow and the shadow cast by the flagpole coincide at a point 3 feet in front of the person.

h = 29.4 f

Step-by-step explanation: (see annex)

I conclude the question of the problem is the height " h " of the flagpole

From the draft in annex, is clear the angle ABC is common to the triangles

ABC and BDE

In triangle BDE  

BE = √ (3)² + (6)²         ⇒ BE = √9 + 36       ⇒BE = √45

BE = 6,71 f

then      sin ∠ ABC  =  6/6.71     ⇒   sin ∠ ABC  = 0,89

then arcsin 0,89      ∠ABC  =  63°

Now in triangle ABC

tan  ∠ ABC  = h/( 12 + 3 )        ⇒   tan  ∠ ABC  = h/15

tan ∠ 63°   =  1.96

Then       1.96  =  h/15

h  =  1.96 * 15

h = 29.4 f

lol we need to see what the question is asking about

step-by-step explanation:

the answer is thin because within context, the stanza concludes the and frail tone the people have toward each other, and the fact that it would be thin, makes the most sense compared to "pliable" or "not hard or firm to the touch". hope this , good luck.

step-by-step explanation:

can i have brainliest