The total value of the $5 bills and $10
bills in a cash box is $410. There are
eight more $10 bills than $5 bills.
How many of each are there?

the number of $5 bills that are there is 22.

the number of $10 bills that are there is 30

Step-by-step explanation:

Let x represent the number of $5 bills that are there.

Let y represent the number of $10 bills that are there.

The total value of the $5 bills and $10 bills in a cash box is $410. This means that

5x + 10y = 410 - - - - - - - - - - - -- - -1

There are eight more $10 bills than $5 bills. This means that

y = x + 8

Substituting y = x + 8 into equation 1, it becomes

5x + 10(x + 8) = 410

5x + 10x + 80 = 410

15x + 80 = 410

15x = 410 - 80 = 330

x = 330/15 = 22

y = x + 8 = 22 + 8

y = 30

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9