John mixed together 9 liters of Brand A fruit drink which contains 14% fruit juice and 8 gallons of Brand B fruit drink which contains 48% fruit juice. What is the percent of fruit juice in the resulting mixture?

41.25%

Step-by-step explanation:

Amount of fruit juice in 9 liters of Brand A fruit drinks which contain 14% fruit juice will be liters.

Again, the amount of fruit juice in 8 gallons i.e. (8 × 4.546) = 36.368 liters of Brand B fruit drinks which contain 48% fruit juice will be liters.

Therefore, mixing those two brands we will get (9 + 36.368) = 45.369 liters of fruit drinks within which (1.26 + 17.456) = 18.716 liters of fruit juice.

So, the % of fruit juice in the mixture will be (Answer)

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.