This circle is centered at the point (3, 2), and the length of its radius is 5. What
is the equation of the circle?
O A. (x-2)2 + (y- 3)2 = 25
O B. (x-3)2 + (x - 2)2 = 25
O c. (x2-3) + (2-2) = 52
OD. (x+3)2 + (y + 2)2 = 5

There is no  corrrect option given but the correct answer is below may help you.

Therefore,

Equation of Circle is

[te](x-3)^{2}+(y-2)^{2}=25[/tex]

Step-by-step explanation:

Given:

Let center be C,

To Find:

Equation of Circle = ?

Solution:

The Equation of Circle with center (h , k) and radius r is given as

Substituting the values we get

Therefore,

Equation of Circle is

[te](x-3)^{2}+(y-2)^{2}=25[/tex]

answer: what in the world is this

step-by-step explanation:

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form