Suppose you roll two fair dice. See the sample space on screen to represent the situation then
determine each of these probabilities.

a. Getting doubles

b. Getting an even sum of at most 6

c. Getting doubles or an even sum of at most 6

d. Getting doubles and an even sum of at most 6

Step-by-step explanation:

Each die has 6 outcomes.  So there are a total of 6×6=36 possible combinations.

a. There are 6 possible doubles.  So the probability is 6/36 = 1/6.

b. There are 9 possible even sums less than or equal to 6.  So the probability is 9/36 = 1/4.

c. There are 6+9−3=12 possible doubles or even sums less than or equal to 6.  So the probability is 12/36 = 1/3.

d. There are 3 possible doubles that are sums less than or equal to 6.  So the probability is 3/36 = 1/12.

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%

linear pair postulates