One of the roots of the quadratic equation x2−5mx+6m2=0 is 36. Find the greatest possible value of the second root. Help needed as soon as possible, Thank You. 50PTS!!

The greatest possible value of the second root is 54

Step-by-step explanation:

Given quadratic equation is

Now factorise the given quadratic equation :

x(x-3m)-2m(x-3m)=0

(x-2m)(x-3m) = 0

x-2m=0 or x-3m=0

∴ x = 2m or x = 3m .

Therefore 2m and 3m are the roots of the given quadratic equation.

Given one of the roots of the quadratic equation is 36

Let 2m=36

Therefore m=18

Substitute m=12 in 2m we have 2(12)=24

Now let 3m=36

Therefore m=12

Substitute m=18 in 3m we have 3(18)=54

Therefore the greatest possible value of the second root is 54

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

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i can't solve unless i know what the line is

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welcome to/p>