Gsuppose that the leathernecks football team has decided to try a play involving a medium pass up the middle (lp). they know that their opponents, the bisons, have three possible defensive strategies (states of nature). one, occurring with a 0.25 chance, is that they will defend against the run, in which case the leathernecks will gain 16 yards. another, occurring with a 0.5 chance, is that they will defend against the medium pass, in which case the leathernecks will gain zero yards. the other possibility, occurring with a 0.25 chance, is that they will defend against the long pass, in which case the leathernecks will gain an average of 8 yards.  what is the expected  utility  of the play for the leathernecks?   assume the team  gets linear utility, ut(yards) = y

step-by-step explanation:   divide the numerator by the denominator to get the decimal

it would still be 193

if divide by 100 then 1.93

i am not sure

answer: i dont know but if you try hard you will get it right : )

step-by-step explanation:

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.

it would be 4 over -2 divided by -1 over 3.

if you want a solution it would be 4

you flip it so it would be 4/-2 divided by 3/-1 then it would be 12/3 and you would simplify it to 4