How do i solve this?
3x-y=2 and 6x+3y=14 as a system of linear equations

Problem:Solve 3x−y=2 and 6x+3y=14
Steps:I will try to solve your system of equations.3x−y=2;6x+3y=14Step:
Solve 3x−y=2 for y:3x−y+−3x=2+−3x(
Add -3x to both sides)−y=−3x+2−y−1=−3x+2−1(Divide both sides by -1)y=3x−2
Step: Substitute (3x−2) for y in 6x+3y=14:6x+3y=146x+3(3x−2)=1415x−6=14(Simplify both sides of the equation)15x−6+6=14+6(Add 6 to both sides)15x=2015x15=2015(Divide both sides by 15)x=43
Step: Substitute (43) for x in y=3x−2:y=3x−2y=3(43)−2y=2
(Simplify both sides of the equation)
y=2 and x=43

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