If a chain of 30 identical short springs linked end-to-end has a stiffness of 450 n/m, what is the stiffness of one short spring?

The stiffness of one short spring is 13500 N/m

Solution:

We are given a chain with number of spring N = 30 and linked end to end ( in series) and stiffness of this chain is 450 N/m

We have to find the stiffness of one short spring

The springs are identical, which means they have same stiffness

The stiffness of one spring in series is given as:

Where,

N is the number of springs

is the stiffness of one spring

is the stiffness of this chain

Substituting,

Therefore,

Thus the stiffness of one short spring is 13500 N/m

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )

walter needs to make at least 5 more cookies but no more than 40. 5 ≥ x ≥ 40;

step-by-step explanation:

walter has to make a minimum of 20 cookies. he already has 15 cookies made, so he must make 5 more to meet the minimum.

the maximum amount of cookies he can make is 55. he already has 15, so he has to make no more than 40 more cookies to meet the maximum.