Prove the divisibility of the following numbers: 7^6+7^5−7^4 by 11

7^6 + 7^5 - 7^4 = 7^4*7^2 + 7^4*7^1 - 7^4*1

7^6 + 7^5 - 7^4 = 7^4(7^2 + 7^1 - 1)

7^6 + 7^5 - 7^4 = 7^4(49 + 7 - 1)

7^6 + 7^5 - 7^4 = 7^4*55

7^6 + 7^5 - 7^4 = 7^4*5*11

7^6 + 7^5 - 7^4 = 11*5*7^4

7^6 + 7^5 - 7^4 = 11*k

Since the number is in the form 11*k, where k = 5*7^4, this proves that 7^6 + 7^5 - 7^4 is a multiple of 11.

step-by-step explanation:

no

step-by-step explanation:

2-7=-5

7-2=5

when you combing like terms for ech expression, 5 and -5. these numbers are not equal to each other.