The sum of two integers is 64. the larger is 16 more than three times the smaller. find the two integers.

12 and 52

Step-by-step explanation:

Let x and y be the 2 integers with x > y, then

x + y = 64 and

x = 3y + 16 ( 16 more than 3 times the smaller )

Substitute x = 3y + 16 into x + y = 64, that is

3y + 16 + y = 64

4y + 16 = 64 ( subtract 16 from both sides )

4y = 48 ( divide both sides by 4 )

y = 12 and x = 3(12) + 16 = 36 + 16 = 52

The 2 integers are 12 and 52

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value

i think the answer is b