What is the equation of a circle whose center is at the origin and whose radius is 16

The equation of the circle is

Step-by-step explanation:  We are given to find the equation of a circle whose center is at the origin and whose radius is 16 units.

The standard equation of a circle with center at (g, h) and radius 'r' units is given by

According to the given information,

Center is at the origin (0, 0), so, (g, h) = (0, 0),

and radius, r = 16.

Therefore, the equation of the circle is given by

Thus, the required equation of the circle is

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b