Use the identities a = a ∩ s and s = b ∪ b and a distributive law to prove that:
1) a = (a ∩ b) ∪ (a ∩ b).
2) if b ⊂ a then a = b ∪ (a ∩ b).

Given that

A = A ∩ S -- (1)

S = B ∪ B -- (2)

To prove:

A = (A ∩ B) ∪ (A ∩ B)

(A ∩ B) ∪ (A ∩ B)

= [(A∪A) ∩ (A∪B)] ∩ [(B∪A) ∩ (B∪B)]

=[A ∩ (A∪B)] ∩ [(A∪B) ∩ S]

=A ∩ (A∪B)

=A

Hence proved.

2) If B ⊂ A then A = B ∪ (A ∩ B)

R.H.S = B ∪ (A ∩ B)

= (B ∪ A) ∩ (B∪B) --(3)

As B is subset of A so

(B ∪ A) = A

From (2)

(B ∪ B) = S

(3) becomes

=A ∩ S

from (1)

A ∩ S = A

Hence proved

24

step-by-step explanation:

if it takes 8 pounds to make 12 divide 12 by 8 and you get 1.5, 1.5 x 16 = 24