Delta airlines quotes a flight time of 2 hours, 5 minutes for its flights from cincinnati to tampa. suppose we believe that actual flight times are uniformly distributed between 2 hours and 2 hours, 20 minutes. what is the probability that the flight will be no more than 5 minutes late?

 0.5

Step-by-step explanation:

Given : Delta Airlines quotes a flight time of 2 hours, 5 minutes for its flights from Cincinnati to Tampa.

i.e. Flight time =   2(60) +5= 125 minutes  [∵ 1 hour = 60 minutes]

Actual flight times are uniformly distributed between 2 hours and 2 hours, 20 minutes.

i.e. In minutes the flight times are between 120 minutes and 140 minutes.

Let x be a uniformly distributed variable in [120 minutes, 140 minutes] that  represents the flight time.

Since the probability density function for x uniformly distributed in [a,b] is

⇒ Probability density function for flight time  :

5 minutes late than usual time = Flight time+ 5 = 125+5 = 130 minutes

Now , the probability that the flight will be no more than 5 minutes late will be :-

Hence, the probability that the flight will be no more than 5 minutes late is 0.5.

-13

step-by-step explanation:

f(x)=2x-5 for f(-4)

f(-4)   means let x=-4

f(-4) = 2(-4) -5

f(-4) =-8-5

      = -13

the correct answer is d

hope this