If you flip a coin and roll a 666-sided die, what is the probability that you will flip a tails and roll at least a 222?

5/12

Step-by-step explanation:

For a coin

Number of sample space = 2

Probability of flipping a tail = 1/2

P(T) = 1/2

For a die

Number of sample space = 6

Let D be the event of rolling at least 2.

D = {2,3,4,5,6}

P(D) = 5/6

P(T) and P(D) = P(T) * P(D)

= 1/2 * 5/6

= 5/12

your answer is the frist one

hop i

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.