Mathematics, 28.01.2020 20:47 red921
Solve the following initial value problem: (t2β20t+51)dydt=y (t2β20t+51)dydt=y with y(10)=1y(10)=1. (find yy as a function of tt.)
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What is the expression in factored form? -x^2 + 3x + 28 a. (x-7)(x-4) b. -(x-7)(x+4) c. (x+4)(x+7) d. -(x-4)(x+7)
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Alina fully simplifies this polynomial and then writes it in standard form. xy2 β 2x2y + 3y3 β 6x2y + 4xy2 if alina wrote the last term as 3y3, which must be the first term of her polynomial in standard form? xy2 5xy2 β8x2y β2x2y
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Solve the following initial value problem: (t2β20t+51)dydt=y (t2β20t+51)dydt=y with y(10)=1y(10)=1....
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