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Mathematics, 28.01.2020 17:41 kevo2024

Jerome solved the equation 1 3 x + 5 6 = 1 as shown. 1. subtraction property of equality: 1 3 x + 5 6 βˆ’ 5 6 = 1 1 βˆ’ 5 6 2. lcd: 1 3 x = 1 6 βˆ’ 5 6 3. multiply by the reciprocal: ( 3 1 ) 1 3 x = βˆ’4 6 ( 3 1 ) 4. solve and simplify: x = βˆ’12 6 = βˆ’2 analyze jerome's steps. in which step did he make an error?

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Jerome solved the equation 1 3 x + 5 6 = 1 as shown. 1. subtraction property of equality: 1 3 x + 5...
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