Asquare that is 5yd on a side is placed inside a rectangle that has a width of 11yd and a length of 17 yd. what is the area of the region inside the rectangle that surrounds the square?

162  sq. yds.

Step-by-step explanation:

Given : A square that is 5yd on a side is placed inside a rectangle that has a width of 11yd and a length of 17 yd.

Then , Area of rectangle = length x width

= 11 yd  x 17 yd = 187 sq. yds.

Area of square = (side)²  

= (5 yd)² = 25  sq. yds.

Now , the area of the region inside the rectangle that surrounds the square will be Area of rectangle - Area of square

= 187 sq. yds.- 25  sq. yds.

=162  sq. yds.

Hence, the area of the region inside the rectangle that surrounds the square is 162  sq. yds. .

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.

$12. that is my answer.