What was the speed during first and also cooldown

Hi Braniac

S = his speed for the 1st 20 mi

(s-2) = His speed for the last 16 mi

We know that :

time= distance/ speed

initial time = cool down time

20/s = 16/(s-2)

Now cross multiply

20(s-2) =16s

20s-40=16s

20s-16s=40

4s = 40

Now we need to divide both sides by 4 so we can find the speed

4s/4 = 40/4

s= 10 mph

His initial speed is 10mph

Now let's find his cool down speed

10-2 = 8mph

His cool down speed is 8mph

I hope that's help :)

If you have any questions please let me know :)

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step-by-step explanation:

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step-by-step explanation:

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