How to solve 2p plus 4s equals 42 and 4p plus 10s equals 140 using solving systems of equations

The solution for the given set of equations is s=28 and p= -35.

Step-by-step explanation:

The given system of equations are:

2p + 4s = 42   and

4p + 10s = 140

To solve for p and s values,

step 1: Multiply the first equation by 2 on both sides. The equation becomes,

4p + 8s = 84

step 2: Subtract the second equation from the first equation.

4p + 8s = 84

-4p - 10s = -140

     - 2s = -56

step 3: The value of s = -56/-2 = 28

step 4: substitute s=28 in the first equation. 2p + 4(28) = 42

                                                                         2p = 42 - 112

                                                                          p= -70/2 = -35

Therefore, the value of s=28 and p= -35.

true? is that what you're asking or do you mean something else?