The equation of line lm is 5x − y = −4. what is the equation of a line perpendicular to line lm in slope-intercept form that contains point (−3, 2)?
a) y = 5x + 13
b) y = negative one fifthx + seven fifths
c) y = negative one fifthx − seven fifths
d) y = 5x − 17

b) y = negative one fifthx + seven fifths

Step-by-step explanation:

Equation of a line in Slope intercept form :   (1)

, where m is slope and c is constant.

Given : The equation of line LM is

Convert it into slope- intercept form, we get

Comparing it to (1) , we get

Let be the slope pf the line perpendicular to LM.

Since the product of slopes of two perpendicular lines is -1.

Therefore ,

Equation of line passing through (-3,2) and having slope will be :-

Hence, the equation of a line perpendicular to line LM in slope-intercept form that contains point (−3, 2) is .

Hence, the correct answer is b) y = negative one fifthx + seven fifths.