Given the function g(x)= 2x2+6 find the indicated value

g(-10) = 206, g(-1) = 8, g() = 6.5

Step-by-step explanation:

Step 1; Take the values given as values of x. The values of x are -10, -1 and . We substitute these values in the function g(x). In the function g(x) we substitute the values of -10, -1, in the place of x in g(x). So for g(-10) we substitute the value of -10 in the place of x and get g(-10). Similarly, we do for the other two values and find g(-1) and g().

Step 2; Substituting the values in the function we get

g(-10) = + 6 = 2(100) + 6 = 206

g(-1) = + 6 = 2(1) + 6 = 8

g() = + 6 = 2 + 6 = 0.5 + 6 = 6.5.

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

you need to show the graph

step-by-step explanation: