Areactangle garden will have dimension of x and y. there will be fencing around the perimeter and also two dividers that will separate the garden into three regions. if you have 50 feet of fencing, what is the lagest area you can produce?

156.25cm^2

Step-by-step explanation:

Perimeter of rectangle: 2(length + width)

P=2(x+y)equation (1)

A= xy equation (2)

From equation (1)

50=2(x+y)

Divide both by two

25=x+y

x=y-25

Then the area:

From equation (2)

A=(y-25)y

The zeros will be y-25=0 and y=0 therefore y=25 and y=0

Then their average is: (25+0)/2 = 12.5

The width is 12.5 and the length is 25-12.5 which is 12.5

X=Length=12.5

Y=width=12.5

The largest area is:

12.5×12.5

156.25cm^2

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00