(1 point) let c be the positively oriented square with vertices (0,0)(0,0), (1,0)(1,0), (1,1)(1,1), (0,1)(0,1). use green's theorem to evaluate the line integral ∫c1y2xdx+9x2ydy∫c1y2xdx+9x2ydy.

Step-by-step explanation:

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

what is the graph

step-by-step explanation: