Solving by elimination 2s + 3b= 28 3s + 2b =27

s=5 b=6

Step-by-step explanation:

2s + 3b = 28.

3s + 2b = 27

First, multiply the first eqn by 3 and multiply the first eqn by 2.

FROM FIRST EQUATION

3 (2s + 3b= 28)

6s + 9b = 84.

FROM SECOND EQUATION

2 (3s+2b =27)

6s + 4b = 54

FIRST EQUATION - SECOND EQUATION

(6s+9b)-(6s+4b) = 84-54

6s+9b-6s-4b = 30

6s-6s+9b-4b=30

5b=30

b=6

Then, substitute b=6 into the first eqn.( the second eqn also can be used)

6s+9(6) =84

6s + 54 = 84

6s = 84-54

6s = 30

s=5

Thank you.

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !