Perimeter of a rectangle is 1300 mil
width is 110 mill less than the length
find length and width

The length is 380 mill and the width is 270 mill.

Step-by-step explanation:

Given:

Perimeter of a rectangle is 1300 mil .

Width is 110 mill less than the length.

Now, to find the length and width.

Let the length be

Thus, the width =

Perimeter = 1300 mil.

Now, to get the length and width of rectangle by putting formula:

Adding both sides by 220 we get:

Dividing both sides by 4 we get:

The length = 380 mill.

Thus, the width =

Therefore, the length is 380 mill and the width is 270 mill.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

my answer got deleted but it's a

step-by-step explanation: